pandemonium_engine/SCSCons/Tool/MSCommon/netframework.py

83 lines
2.6 KiB
Python

# MIT License
#
# Copyright The SCons Foundation
#
# Permission is hereby granted, free of charge, to any person obtaining
# a copy of this software and associated documentation files (the
# "Software"), to deal in the Software without restriction, including
# without limitation the rights to use, copy, modify, merge, publish,
# distribute, sublicense, and/or sell copies of the Software, and to
# permit persons to whom the Software is furnished to do so, subject to
# the following conditions:
#
# The above copyright notice and this permission notice shall be included
# in all copies or substantial portions of the Software.
#
# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY
# KIND, EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE
# WARRANTIES OF MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS BE
# LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN ACTION
# OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN CONNECTION
# WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE SOFTWARE.
"""
MS Compilers: .Net Framework support
"""
import os
import re
from .common import read_reg, debug
# Original value recorded by dcournapeau
_FRAMEWORKDIR_HKEY_ROOT = r'Software\Microsoft\.NETFramework\InstallRoot'
# On SGK's system
_FRAMEWORKDIR_HKEY_ROOT = r'Software\Microsoft\Microsoft SDKs\.NETFramework\v2.0\InstallationFolder'
def find_framework_root():
# XXX: find it from environment (FrameworkDir)
try:
froot = read_reg(_FRAMEWORKDIR_HKEY_ROOT)
debug("Found framework install root in registry: %s", froot)
except OSError:
debug("Could not read reg key %s", _FRAMEWORKDIR_HKEY_ROOT)
return None
if not os.path.exists(froot):
debug("%s not found on fs", froot)
return None
return froot
def query_versions():
froot = find_framework_root()
if froot:
contents = os.listdir(froot)
l = re.compile('v[0-9]+.*')
versions = [e for e in contents if l.match(e)]
def versrt(a,b):
# since version numbers aren't really floats...
aa = a[1:]
bb = b[1:]
aal = aa.split('.')
bbl = bb.split('.')
# sequence comparison in python is lexicographical
# which is exactly what we want.
# Note we sort backwards so the highest version is first.
return (aal > bbl) - (aal < bbl)
versions.sort(versrt)
else:
versions = []
return versions
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# tab-width:4
# indent-tabs-mode:nil
# End:
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